[nodejs] Debugging Gulp fails in Chrome

[r***@gmail.com]

Hi,
I have followed the article
(https://stackoverflow.com/questions/40033298/how-to-debug-a-gulp-task) to
debug gulp file using chrome. My gulpfile.js looks like this:
var gulp = require('gulp');
// Gulp 4
debugger;
gulp.task('cleanTemp', function (done) {
console.log('Hello world!');
done();
});

When I execute the command from my working folder:
node --inspect-brk ./node_modules/gulp/node_modules/.bin/gulp cleanTemp

I am getting an error:
Debugger attached.
C:\Workspace\Projects\Eclipse\CommsProc\Source\HttpServer\node_modules\gulp\node_modules\.bin\gulp:2
basedir=$(dirname "$(echo "$0" | sed -e 's,\\,/,g')")
^^^^^^^

SyntaxError: missing ) after argument list
at createScript (vm.js:80:10)
at Object.runInThisContext (vm.js:139:10)
at Module._compile (module.js:617:28)
at Object.Module._extensions..js (module.js:664:10)
at Module.load (module.js:566:32)
at tryModuleLoad (module.js:506:12)
at Function.Module._load (module.js:498:3)
at Function.Module.runMain (module.js:694:10)
at startup (bootstrap_node.js:204:16)
at bootstrap_node.js:625:3
Waiting for the debugger to disconnect...

What am I doing wrong. What does this message mean: basedir=$(dirname
"$(echo "$0" | sed -e 's,\\,/,g')")

Kind Regards,
Janusz
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[Rashik Ansar Shaik]

i think its __dirname

Hi,
I have followed the article (
https://stackoverflow.com/questions/40033298/how-to-debug-a-gulp-task) to
var gulp = require('gulp');
// Gulp 4
debugger;
gulp.task('cleanTemp', function (done) {
console.log('Hello world!');
done();
});
node --inspect-brk ./node_modules/gulp/node_modules/.bin/gulp cleanTemp
Debugger attached.
C:\Workspace\Projects\Eclipse\CommsProc\Source\HttpServer\node_modules\gulp\node_modules\.bin\gulp:2
basedir=$(dirname "$(echo "$0" | sed -e 's,\\,/,g')")
^^^^^^^
SyntaxError: missing ) after argument list
at createScript (vm.js:80:10)
at Object.runInThisContext (vm.js:139:10)
at Module._compile (module.js:617:28)
at Object.Module._extensions..js (module.js:664:10)
at Module.load (module.js:566:32)
at tryModuleLoad (module.js:506:12)
at Function.Module._load (module.js:498:3)
at Function.Module.runMain (module.js:694:10)
at startup (bootstrap_node.js:204:16)
at bootstrap_node.js:625:3
Waiting for the debugger to disconnect...
What am I doing wrong. What does this message mean: basedir=$(dirname
"$(echo "$0" | sed -e 's,\\,/,g')")
Kind Regards,
Janusz
--
Job board: http://jobs.nodejs.org/
https://gist.github.com/othiym23/9886289#file-moderation-policy-md
https://github.com/joyent/node/wiki/Mailing-List-Posting-Guidelines
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[r***@gmail.com]

Yeah. But what about dirname. Any solution?

Kind Regards,
Janusz

Hi,
I have followed the article (
https://stackoverflow.com/questions/40033298/how-to-debug-a-gulp-task) to
var gulp = require('gulp');
// Gulp 4
debugger;
gulp.task('cleanTemp', function (done) {
console.log('Hello world!');
done();
});
node --inspect-brk ./node_modules/gulp/node_modules/.bin/gulp cleanTemp
Debugger attached.
C:\Workspace\Projects\Eclipse\CommsProc\Source\HttpServer\node_modules\gulp\node_modules\.bin\gulp:2
basedir=$(dirname "$(echo "$0" | sed -e 's,\\,/,g')")
^^^^^^^
SyntaxError: missing ) after argument list
at createScript (vm.js:80:10)
at Object.runInThisContext (vm.js:139:10)
at Module._compile (module.js:617:28)
at Object.Module._extensions..js (module.js:664:10)
at Module.load (module.js:566:32)
at tryModuleLoad (module.js:506:12)
at Function.Module._load (module.js:498:3)
at Function.Module.runMain (module.js:694:10)
at startup (bootstrap_node.js:204:16)
at bootstrap_node.js:625:3
Waiting for the debugger to disconnect...
What am I doing wrong. What does this message mean: basedir=$(dirname
"$(echo "$0" | sed -e 's,\\,/,g')")
Kind Regards,
Janusz

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